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[tex]Moles \: of \: H _2SO_{4} \: is \: is \: 2.9 \: moles.[/tex]
[tex]Moles \: of \: C _2H _4O _2 \: is \: 1.4 \: moles. [/tex]
[tex]Moles \: of \: NaOH\: is \: 5.8 \: moles.[/tex]
The total number of moles of hydrogen in all the compounds = 5.8 mol.
The number of hydrogen present in sulphuric acid = 2.
Let the number of moles of the sulphuric acid present
be X. [tex]Number \:of \: mol \: of H_2SO _4 \:present [/tex]
is,
[tex]1 \: mole \: of \:H _2SO_{4} \: has \: 2 \: moles \: of \: H.[/tex]
[tex]X = 5.8 \times \frac{1}{2} [/tex]
[tex]X = 2.9 \: moles[/tex]
Thus, the number of moles of sulphuric acid present is 2.9 moles.
Number of hydrogen present in acetic acid = 4
Let the number of moles of acetic acid be Y.
[tex]Number \:of \: mol \: of C _2H _4O _2 \:present [/tex]
is,
[tex]Y = 5.8 \times \frac{1}{4} [/tex]
[tex]Y = 1.4 \: moles[/tex]
Thus, the number of moles of acetic acid is 1.4 moles.
The number of hydrogen present in sodium hydroxide = 1.
Let the number of moles of sodium hydroxide be Z.
[tex]Number \:of \: mol \: of \: NaOH\:present [/tex]
is,
[tex]Z = 5.8 \times \frac{1}{1} [/tex]
[tex]Z = 5.8 \: moles[/tex]
Thus, the number of moles of sodium hydroxide is 5.8 moles.
5.8 moles. [tex]Therefore, \: moles \: of \: H _2SO_{4} \: is \: [/tex]
[tex]is \: 2.9 \: moles. \: \:Moles \: of \: C _2H _4O _2 \: is[/tex]
[tex]is \: 1.4 \: moles. \: Moles \: of \: NaOH\: is[/tex]
5.8 moles.
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