IDNLearn.com is the place where your questions are met with thoughtful and precise answers. Get timely and accurate answers to your questions from our dedicated community of experts who are here to help you.
[tex]Moles \: of \: H _2SO_{4} \: is \: is \: 2.9 \: moles.[/tex]
[tex]Moles \: of \: C _2H _4O _2 \: is \: 1.4 \: moles. [/tex]
[tex]Moles \: of \: NaOH\: is \: 5.8 \: moles.[/tex]
The total number of moles of hydrogen in all the compounds = 5.8 mol.
The number of hydrogen present in sulphuric acid = 2.
Let the number of moles of the sulphuric acid present
be X. [tex]Number \:of \: mol \: of H_2SO _4 \:present [/tex]
is,
[tex]1 \: mole \: of \:H _2SO_{4} \: has \: 2 \: moles \: of \: H.[/tex]
[tex]X = 5.8 \times \frac{1}{2} [/tex]
[tex]X = 2.9 \: moles[/tex]
Thus, the number of moles of sulphuric acid present is 2.9 moles.
Number of hydrogen present in acetic acid = 4
Let the number of moles of acetic acid be Y.
[tex]Number \:of \: mol \: of C _2H _4O _2 \:present [/tex]
is,
[tex]Y = 5.8 \times \frac{1}{4} [/tex]
[tex]Y = 1.4 \: moles[/tex]
Thus, the number of moles of acetic acid is 1.4 moles.
The number of hydrogen present in sodium hydroxide = 1.
Let the number of moles of sodium hydroxide be Z.
[tex]Number \:of \: mol \: of \: NaOH\:present [/tex]
is,
[tex]Z = 5.8 \times \frac{1}{1} [/tex]
[tex]Z = 5.8 \: moles[/tex]
Thus, the number of moles of sodium hydroxide is 5.8 moles.
5.8 moles. [tex]Therefore, \: moles \: of \: H _2SO_{4} \: is \: [/tex]
[tex]is \: 2.9 \: moles. \: \:Moles \: of \: C _2H _4O _2 \: is[/tex]
[tex]is \: 1.4 \: moles. \: Moles \: of \: NaOH\: is[/tex]
5.8 moles.
To know more about acetic acid, refer to the below link:
https://brainly.com/question/24194581
#SPJ4