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A ball is thrown upward at time t=0 from the ground with an initial velocity of 18 m/s (~ 40 mph). what is the total time it is in the air? assume that g = 10 m/s2.

Sagot :

The total time it is in the air for the ball is 3.672 s

Given:

Initial velocity = 18 m/s

We have to find the total time the ball is in the air.

By using the formula, we get,

t = v - u/a

Where t = time to reach the maximum height

v = final velocity of the ball = 0 m/s

u = initial velocity of ball = 18 m/s

a = acceleration due to gravity = -9.8

Acceleration of gravity is taken as negative because the ball is moving in the opposite direction.

t = 0 - 8/-9.8

t = 1.836 sec

Thus, time is taken by the ball to reach the ground again = time taken to reach the maximum height

So, the Total time required for the ball to reach the ground = 2t = 2 × 1.836

Total time required for the ball to reach the ground = 3.672 s

Hence, the total time it is in the air for the ball is 3.672 sec.

To learn more about time and acceleration, visit: https://brainly.com/question/13135868

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