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i am standing on the upper deck of the football stadium. i have an egg in my hand. i am going to drop it and you are going to try to catch it. you are standing on the ground.​ apparently, you do not want to stand directly under​ me; in​ fact, you would like to stand as far to one side as you can so that if i accidentally release​ it, it​ won't hit you on the head. if you can run at feet per second and i am at a height of ​feet, how far away can you stand and still catch the egg if you start running when i let​ go?

Sagot :

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Correct Option: Around 25 ft away you can stand and still catch the egg if you start running when I let​ go.

What is the acceleration due to gravity?

The force of gravity (from the distribution of mass within the Earth) and centrifugal force (from the rotation of the Earth), both represented by the letter g, are the net acceleration that is applied to things. This acceleration is given in meters per second squared (m/s²) or, equivalently, in newtons per kilogram (N/kg) in SI units.

Explanation:

We have two simultaneous trajectories if the person on the ground begins to run at the same moment the egg is dropped:

1 ) Egg falling:

The kinematic equation is as follows:

yf-y₀ = 1/2* g* t²

0-100 ft = 1/2* (-32.15 ft/s²)* t²

⇒ t = 2.5 sec.

2) Person on the ground running away:

In order to be able to run away, and then return to catch the egg, running at a constant speed, he must run during exactly half of the time that the egg is falling, i.e., 1.25 sec.

We can get the distance from the equation:

v = (xf-x₀) / (tfi-t₀)

If we choose t₀=0 and x₀ = 0, we can find out xf:

xf = v*t = 20 ft/sec*1.25 sec

   = 25 ft.

Hence,  Around 25 ft away you can stand and still catch the egg if you start running when he lets​ go.

To know more about acceleration due to gravity, visit:

https://brainly.com/question/13860566

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