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Sagot :
The equation of the circle is given by (C) (x-3)² + (y + 4)² = 9
All points in a plane that are at a specific distance from a specific point, the center, form a circle. In other words, it is the curve that a moving point in a plane draws to keep its distance from a specific point constant. The radius of a circle is the separation between any point on the circle and its center.
The equation of the circle in the general form is given by the
(x-a)²+(y-b)²=r²
Where (a,b) is the co-ordinates of the center of the circle and the radius is r.
Now the center of the circle is given at (3,-4) and the radius is r.
We know that the general equation of a circle is [tex]{\displaystyle (x-a)^{2}+(y-b)^{2}=r^{2}}[/tex]
Substituting the values in the equation we get:
(x-3)²+(y-(-4))²=(3)²
or, (x-3)²+(y+4)²=9
Hence the equation of the circle is (x-3)² + (y + 4)² = 9.
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