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(4x-1)(3x^2+3x-5) (4x−1)(3x 2 +3x−5)

Sagot :

Beinggreat78idn

Hi.

Answer:

[tex]\left(4x-1\right)^2\left(3x^2+3x-5\right)^2[/tex]

Step-by-step explanation:

[tex](aa=a^2) \left(4x-1\right)\left(4x-1\right)=\left(4x-1\right)^2\\=\left(4x-1\right)^2\left(3x^2+3x-5\right)\left(3x^2+3x-5\right)\\\left(3x^2+3x-5\right)\left(3x^2+3x-5\right)=\left(3x^2+3x-5\right)^2\\=\left(4x-1\right)^2\left(3x^2+3x-5\right)^2[/tex]

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