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Determine the volume of hydrogen gas needed to react completely with
5.00 L of oxygen gas to form water,


Sagot :

The volume of hydrogen needed to react with 5.00 L of oxygen based on the mole ratio is 10.00 L.

What volume of hydrogen gas is needed to react with 5.00 L of oxygen?

The volume of hydrogen gas is needed to react with 5.00 L of oxygen is determined from the mole ratio of the reactants as shown in the equation of reaction below:

Equation of reaction:  2 H₂ + O₂ → 2 H₂O

Mole ratio of hydrogen to oxygen = 2 : 1

Moles of gases occupies equal volume

Therefore, Volume ratio of hydrogen to Oxygen = 2 : 1

Volume of hydrogen needed to react with 5.00 L of oxygen = 5.00 * 2

Volume of hydrogen needed to react with 5.00 L of oxygen = 10.00 L

In conclusion, the volume of hydrogen required is obtained from the mole ratio of hydrogen and oxygen in the reaction.

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