Explore a diverse range of topics and get answers from knowledgeable individuals on IDNLearn.com. Discover reliable and timely information on any topic from our network of knowledgeable professionals.
Their final velocity would be 0.118 m/s
Calculation
M1= 168000kg, V1= 0.291 m/s
M2= 117000kg, V2 = 0.128 m/s
According to conservation of momentum,
M1V1 + M2V2 = V(M1+M2)
⇒V = [tex]\frac{168000 * 0.291-117000*0.128}{168000+117000}[/tex]
=[tex]\frac{48888-14976}{285000}[/tex]
=0.118 m/s
Thus, the trains will finally get to the velocity of 0.118 m/s
To know more about velocity, visit:
https://brainly.com/question/18084516
#SPJ4