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35. What is the equation of the line that is parallel to y = 4x + 3 and passes through the point (2, 6) ?

Sagot :

The equation of the line that is parallel to y = 4x ₊ 3 and passes through the point (2,6) is  y = 4x ₋ 2.

The slope of the preceding equation is 4 because it is in slope intercept form. The slope of an equation is always equal for parallel lines, hence the slope of the equation we are requested to create is also 4.  We are given that this line passes through (2,6).

In the absence of intersection, two lines are said to be parallel. Each line has the same slope. In the event where m₁=m₂, f(x)=m₁x+b₁ and g(x)=m₂x+b₂ are. parallel

In order to write in y = mx +b form, we need to solve for b (the y-intercept).  

Given, x=2, y=6, and m = 4.

6 = (4) (2) ₊ b

simplify

6 = 8 ₊ b

solve for b.

b = 6 ₋ 8

b = ₋2

So the equation of the parallel line is   y = 4x ₋ 2

Hence we get the equation of the line that is parallel to y = 4x ₊ 3 and passes through the point (2,6) is y = 4x ₋ 2

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