IDNLearn.com is designed to help you find accurate answers with ease. Our platform is designed to provide quick and accurate answers to any questions you may have.
Sagot :
The calculated energy is 3.97×10⁻²¹J
A single photon has an energy of hv or = (h/2), where h is the Planck constant of 6.626 x 10-34 Joule-sec. If the photon's frequency is known, we may apply the formula E = h f to determine a photon's energy. The equation E = h c can be used to determine a photon's energy if its wavelength is known.
The photon has a 3.97 1021 J energy.
E=hf, with
Planck's constant is h, and the photon's frequency is f.
The second equation is f=c, where c is the speed of light and is the photon's wavelength.
F=c, so we can write
E=hcλ
=6.626×10⁻³⁴J⋅s×2.998×10⁸m⋅s⁻¹/5.00×10⁴×10⁻⁹
=3.97×10⁻²¹J
Learn more about Energy here-
https://brainly.com/question/1932868
#SPJ9
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! Your questions deserve precise answers. Thank you for visiting IDNLearn.com, and see you again soon for more helpful information.
