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The width, of a rectangle is 1/2 of its length. What are the sides of the rectangle if its perimeter is 63 in

Sagot :

Answer:

Step-by-step explanation:

Givens

w = 1/2 L

width = w

Perimeter = 63 in

Formula

P = 2w + 2L

63 = 2(1/2L) + 2L

Solution

63 = L + 2L

63 = 3 L                         Divide by 3

63/3 = 3L/3

L = 21

w= 21/2 = 10.5

Check

P = 2L + 2w

P = 2*21 + 2*10.5

P = 42 + 21

P = 63                          which it should.