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Sagot :
Answer:
See attachment.
Step-by-step explanation:
Slope-intercept form:
[tex]\boxed{y=mx+b}[/tex]
where:
- m = slope
- b = y-intercept
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Given inequality:
[tex]3x-2y < 10[/tex]
Rearrange the given inequality to make y the subject:
[tex]\implies 3x-2y+2y < 10+2y[/tex]
[tex]\implies 3x < 10+2y[/tex]
[tex]\implies 3x-10 < 10+2y-10[/tex]
[tex]\implies 3x-10 < 2y[/tex]
[tex]\implies 2y > 3x-10[/tex]
[tex]\implies \dfrac{2y}{2} > \dfrac{3}{2}x-\dfrac{10}{2}[/tex]
[tex]\implies y > \dfrac{3}{2}x-5[/tex]
Compare this with the slope-intercept form.
Therefore:
- slope = ³/₂
- y-intercept = (0, -5)
When graphing inequalities:
- < or > : dashed line.
- ≤ or ≥ : solid line.
- < or ≤ : shade under the line.
- > or ≥ : shade above the line.
To graph the given inequality using its slope and y-intercept:
- Plot the y-intercept → point (0, -5).
- As the slope is ³/₂, plot another point 3 units up and 2 units right from (0, -5) → point (2, -2).
- Draw a dashed straight line through the two points.
- Shade above the line.
Learn more about graphing inequalities here:
https://brainly.com/question/27743925

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