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Marta uses 1 piece of paper and 1 piece of ribbon to make kites. The paper comes in packs of 3 and the ribbon comes in packs of 4. What is the least number of kites Marta can make without any supplies left over?

Sagot :

Paper: 3/ 3/ 3/ 3
Ribbon: 4/ 5/ 6/ leftover 3
Kites: 3/ 3/ 3/ 3

Leftover: 1/ 2/ 3/ 0

Make a graph like that that solves the problem.
ThetiipLajuxidn

Answer:

12 kites because 12 is the least common multiple of 3 and 4

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