Nayraidn
Answered

IDNLearn.com: Your destination for reliable and timely answers to any question. Discover reliable and timely information on any topic from our network of knowledgeable professionals.

what are the zeros of -3x^2+10x+12

Sagot :

Konrad509idn
[tex] -3x^2+10x+12=0\\ \Delta=10^2-4\cdot(-3)\cdot12=100+144=244\\ \sqrt{\Delta}=\sqrt{244}=2\sqrt{61}\\ x_1=\dfrac{-10-2\sqrt{61}}{2\cdot(-3)}=\dfrac{-10-2\sqrt{61}}{-6}=\dfrac{5+\sqrt{61}}{3}\\ x_2=\dfrac{-10+2\sqrt{61}}{2\cdot(-3)}=\dfrac{-10+2\sqrt{61}}{-6}=\dfrac{5-\sqrt{61}}{3}\\[/tex]
Your engagement is important to us. Keep sharing your knowledge and experiences. Let's create a learning environment that is both enjoyable and beneficial. Your questions deserve precise answers. Thank you for visiting IDNLearn.com, and see you again soon for more helpful information.