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If you are given a 0. 31 g piece of sodium metal to react with water, how many moles of hcl would it take to neutralize the sodium hydroxide produced?.

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If you are given a 0. 31 g piece of sodium metal to react with water, 0.0134  moles of hcl would it take to neutralize the sodium hydroxide produced

Get a balanced equation to represent Na and water

2Na+2H2O -->2NaOH+H2

get moles of NaOH

0.31g Na/22.98 g (MW) = 0.0134 moles( Na)

2:2 ratio Na to NAOH ratio from equation which is balanced there fore moles of Na =  NAOH mass

HCL+NAOH --> NACL+H2O Is a 1:1 ratio between the OH- and the H+  so the moles of OH= the moles of H

moles of NaOH = HCL moles

0.0134moles

Strongly alkaline sodium hydroxide (also known as caustic soda) and hydrogen gas combine to generate a colorless solution. Exothermic reaction, as in this. Heat causes the sodium metal to ignite and may burn with a distinctive orange flame. When sodium is introduced to water, it melts and congeals into a ball that bobs and weaves on the surface. Before the sodium dissipates, the mixture rapidly fizzles and may create orange flame hydrogen.

Learn more about sodium hydroxide here:

https://brainly.com/question/24010534

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