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Sagot :
We will have the following:
First, we know that the Richter scale follows a base 10 log of energy we will have the following data from this equation:
[tex]\log (E)=4.4+1.5M[/tex]1925:
[tex]\log E=4.4+1.5(6.8)\Rightarrow_{}\log _{}(E)=14.6[/tex][tex]\Rightarrow E^{}=10^{14.6}\Rightarrow E\approx3.981\cdot10^{14}[/tex]So, the energy released by the earthquake with a magnitude of 6.8 in 1295 was os approximately 3.981*10^14 Joules.
1978:
[tex]\log (E)=4.4+1.5(5.2)\Rightarrow\log (E)=12.2[/tex][tex]\Rightarrow E=10^{12.2}\Rightarrow E\approx1.585\cdot10^{12}[/tex]Now, we determine the difference in energy released:
[tex]E_f=3.981\cdot10^{14}-1.585\cdot10^{12}\Rightarrow E_f\approx3.965\cdot10^{14}[/tex]So, the earthquake in 1925 released approximately 3.965*10^14 more joules than the earthquake in 1978.
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