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we have the following:
[tex]y-9=-\frac{1}{3}(x-4)[/tex]we reduce the equation to the following form:
[tex]y=mx+b[/tex]where, m is the slope, now
[tex]\begin{gathered} y=-\frac{1}{3}x+\frac{4}{3}+9 \\ y=-\frac{1}{3}x+\frac{31}{3} \end{gathered}[/tex]therefore, the slope is -1/3
the point:
[tex]\begin{gathered} x=0 \\ y=-\frac{1}{3}\cdot0+\frac{31}{3} \\ y=\frac{31}{3} \end{gathered}[/tex]the point is (0, 31/3)