Discover new knowledge and insights with IDNLearn.com's extensive Q&A platform. Get the information you need from our community of experts who provide accurate and comprehensive answers to all your questions.
Sagot :
Given a line made by two points (x1, y1) and (x2, y2), its slope (m) is computed as:
[tex]m\text{ = }\frac{y_2-y_1}{x_2-x_1}[/tex]In this case, the points are (-2, -1) and (1, 8). The slope is:
[tex]m_1\text{ = }\frac{8\text{ - (-1)}}{1\text{ - (-2)}}=\frac{9}{3}=3[/tex]Two lines are perpendicular if the multiplication of their slopes is equal to -1. Then:
[tex]\begin{gathered} m_1\cdot m_2=-1 \\ m_2\text{ = }\frac{-1}{m_1} \\ m_2\text{ = }\frac{-1}{3} \end{gathered}[/tex]Isolating y in option D:
2x = -6y +3
2x - 3 = -6y
2/(-6)x - 3/(-6) = y
-1/3x + 1/2 = y
where -1/3 is its slope. Then, this line is perpendicular to line segment AB
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Find clear answers at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.
