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A farmer needs to administer a dose of albendazole dewormer to a cow that weighs 992 lbs. The dosage recommended by his veterinarian is 10 mg per kg of body weight. How many mg of albendazole should the farmer administer? [1 kg = 2.205 lbs]Calculate the weight of this cow in kg. Round to 4 decimal places.Then, using the exact weight in kg (not your rounded weight) and the medical conversion, determine the dose that the cow should get in mg. Round to two decimal places.

A Farmer Needs To Administer A Dose Of Albendazole Dewormer To A Cow That Weighs 992 Lbs The Dosage Recommended By His Veterinarian Is 10 Mg Per Kg Of Body Weig class=

Sagot :

Given:

Weight of cow = 992 lbs

Recommended dosage = 10 mg per kg

Let's find the amount of mg the farmer should administer.

Let's first find the weight of the cow in kg.

Where:

1 kg = 2.205 lbs

992 lbs will be:

[tex]\frac{992}{2.205}=449.887\text{ kg}[/tex]

The weight of the cow in kg is 449.8866 kg.

Since 10 mg per kg should be administered, to find the amount of mg to be administered to the cow, we have:

[tex]449.887*10=4498.87\text{ mg}[/tex]

Therefore, the amount of mg the farmer should administer is 4498.87 mg.

Part B.

Given:

1 mL of liquid = 125 mg of albendazole

Let's find the amount of mL of the liquid the farmer should administer.

Since 1 mL = 125 mg, and the amount of mg the farmer should administer is 4498.87 mg, we have:

[tex]\frac{4498.87}{125}*1\text{ mL = 35.99 mL}[/tex]

Therefore, the farmer should administer 35.99 mL of the liquid

ANSWER:

Part A.

Weight of the cow in kg = 449.8866

Amount of mg the farmer should administer = 4498.87 mg

Part B.

Amount of liquid the farmer should administer = 35.99 mL

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