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ZABC is a straight angle.Find mZABX and mZCBX.AÀ(14x + 70)/(20x + 8)BOmZABX = =mZCBX =

ZABC Is A Straight AngleFind MZABX And MZCBXAÀ14x 7020x 8BOmZABX MZCBX class=

Sagot :

m∠ABX = 112

m∠CBX=68

1)

According to the segment addition postulate, in those 2 angles summed we have ∠ABC.

2) ABC is equal to 180º

∠ABX +∠CBX =∠ABC

Plugging into them

14x +70+20x+8=180º

34x +78 =180

34x +78-78=180-78

34x=102 : 34

x= 3

So m∠ABX = 14(3) +70 = 112 and m∠CBX =180-112=68

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