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A cone has a radius of 10 ft and a height of 22ft

A Cone Has A Radius Of 10 Ft And A Height Of 22ft class=

Sagot :

Hello!

In this exercise, I will calculate the area and the volume of this cone.

First, look at the image below and let's write some important information:

So, we know that:

• r, = 10ft

,

• h, = 22ft

,

• g, = 24

,

• pi ,= 3.14

Let's solve this using the formulas:

Area:

[tex]\begin{gathered} A=(\pi\times r^2)+(\pi\times r\times g) \\ A=(3.14\times10^2)+(3.14\times10\times24.2) \\ A=(3.14\times100)+759.88 \\ A=314+759.88 \\ A=1073.88ft^2 \end{gathered}[/tex]

Volume:

[tex]\begin{gathered} V=\frac{\pi\times r^2\times h}{3} \\ V=\frac{3.14\times10^2\times22}{3} \\ V=\frac{3.14\times100\times22}{3}=\frac{6908}{3}=2302.66ft^3 \end{gathered}[/tex]

View image LyllianaB406394
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