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Sagot :
Given the equation of the parabola:
[tex]y=x^2-6x+5[/tex]Find the vertex form of the parabola.
Given a vertical parabola with the vertex located at (h,k) and leading coefficient of a, the vertex form of the parabola is:
[tex]y=a(x-h)^2+k[/tex]To find the vertex form of the parabola, we must complete squares of the given equation.
Add and subtract 9 to the equation:
[tex]y=x^2-6x+9+5-9[/tex]
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