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Sagot :
Answer:
0.154 g of CO2 (carbon dioxide).
Explanation:
What is given?
Grams of glucose (C6H12O6) = 0.315 g.
Molar mass of glucose (C6H12O6) = 180 g/mol.
Molar mass of carbon dioxide (CO2) = 44 g/mol.
Chemical equation:
[tex]C_6H_{12}O_6\rightarrow2C_2H_6O+2CO_2.[/tex]Step-by-step solution:
First, we have to convert 0.315 g of glucose (C6H12O6) to grams using its given molar mass. The conversion will be:
[tex]0.315\text{ g C}_6H_{12}O_6\cdot\frac{1\text{ mol C}_6H_{12}O_6}{180\text{ g C}_6H_{12}O_6}=0.00175\text{ moles C}_6H_{12}O_6.[/tex]Now, you can see in the chemical equation that 1 mol of glucose (C6H12O6) reacted produces 2 moles of CO2, so the number of moles of CO2 that will produce 0.00175 moles of C6H12O6 based on this information is:
[tex]0.00175\text{ moles C}_6H_{12}O_6\cdot\frac{2\text{ moles CO}_2}{1\text{ mol C}_6H_{12}O_6}=0.00350\text{ moles CO}_2.[/tex]And the final step is to convert from 0.00350 moles of CO2 to grams using its given molar mass, so the calculation would be:
[tex]0.00350\text{ moles CO}_2\cdot\frac{44\text{ g CO}_2}{1\text{ mol CO}_2}=0.154\text{ g CO}_2.[/tex]The answer is that we will produce 0.154 g of CO2 (carbon dioxide) from 0.315 g of glucose.
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