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Use Law of sines to solve for this problem. Round your answer to the nearest TENTH.

Use Law Of Sines To Solve For This Problem Round Your Answer To The Nearest TENTH class=

Sagot :

We will have the following:

AB:

[tex]\begin{gathered} \frac{15}{sin(70)}=\frac{AB}{sin(45)}\Rightarrow AB=\frac{15sin(45)}{sin(70)} \\ \\ \Rightarrow AB=11.28730979...\Rightarrow AB\approx11.3 \end{gathered}[/tex]

So, the measure of segment AB is approximately 11.3 units.

BC:

[tex]\begin{gathered} \frac{BC}{sin(65)}=\frac{15}{sin(70)}\Rightarrow BC=\frac{15sin(65)}{sin(70)} \\ \\ \Rightarrow BC=14.46708903...\Rightarrow BC\approx14.5 \end{gathered}[/tex]

So, the measure of segment BC is approximately 14.5 units.

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