IDNLearn.com: Where curiosity meets clarity and questions find their answers. Our platform is designed to provide trustworthy and thorough answers to any questions you may have.
Sagot :
SOLUTION
Step1: Write out the giving equation
[tex]7-4x=7y[/tex]Step2: Write out the equation in form of y=mx+c
[tex]\begin{gathered} 7-4x=7y \\ 7y=-4x+7 \\ \text{ Divide both sides by 7} \\ y=-\frac{4}{7}x+1 \end{gathered}[/tex]Then the gradient of the equation is the coefficient of x
[tex]\text{ gradient, m=-}\frac{4}{7}[/tex]Two lines are parallel if their gradient is the same
Hence the second line will have a gradient of
[tex]m_2=-\frac{4}{7}[/tex]Step4: Apply the slope and one point form to find the gradient of the line parallel to 7-4x=7y
[tex]\begin{gathered} y-y_1=m_2(x-x_1) \\ \text{where the point given is (2,0)} \\ y_1=0,x_1=2 \end{gathered}[/tex]The substitute the parameters into the formula
[tex]\begin{gathered} y-0=-\frac{4}{7}(x-2) \\ y=-\frac{4}{7}x+\frac{8}{7} \end{gathered}[/tex]Therefore the equation of the line is y = -4/7x+8/7
The right option is C
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your search for solutions ends here at IDNLearn.com. Thank you for visiting, and come back soon for more helpful information.
