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Find all missing parts of the triangle. When necessary, round answers to the nearest tenth. ONLY enter the answer, not units ordegree symbols.B28САB (angle B)=a (side a)b(side b)Blank 1:Blank 2:Blank 3:

Sagot :

To find all the missing parts of the triangle, we need to know the triangle trigonometry:

We can find the sides first, with the angle A=28 and the hypotenuse=7

[tex]\begin{gathered} \sin (28)=\frac{a}{7} \\ a=7\sin (28) \\ a=3.3\text{ } \end{gathered}[/tex]

Now, the side b:

[tex]\begin{gathered} \cos (28)=\frac{b}{7} \\ b=7\cos (28) \\ b=6.2 \end{gathered}[/tex]

Having all the sides, we can calculate the angle B:

[tex]\begin{gathered} \sin (B)=\frac{6.2}{7} \\ B=\sin ^{-1}(\frac{6.2}{7}) \\ B=62.3\text{ degr}ees \end{gathered}[/tex]

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