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why is 0.08 x -0.1 = -0.008 ? when I multiply 0.08 x -0.1 i gives me -0.02 Please confirm the calculations,AnswerGiven:•Mass of marble A, m1 = 0.08 kg•Mass of marble B, m2 = 0.05 kg•Velocity of marble A before collision(initial velocity of marble A), u1 = 0.5 m/s•Velocity of marble A after collision(final velocity of marble A), v1 = -0.1 m/sLet's find the resulting velocity of marble B after the collision.Since there is no force on the system, let's make use of momentum conservation.formula:m1u1+m2u2=m1v1+m2v2Here, the resulting velocity for marble B is v2.Let's rewrite the formula for v2.We have:v2=m1u1+m2u2−m1v1 m2m1 = 0.08 kgm2 = 0.05 kgu1 = 0.5 m/su2 is the initial velocity of marble B = 0 m/sv1 = -0.1 m/sHence, we have:v2=(0.08∗0.5)+(0.05∗0)+(0.08∗−0.1) 0.05v2=(0.04)+(0)+(−0.008) 0.05v2=0.04−0.0080.05v2=0.0480.05v2=0.96 m/sTherefore, the resulting velocity of marble B after the collision is 0.96 m/s.

Sagot :

(a). Give data:

* The mass of the marble A is m1 = 0.08 kg

* The mass of marble B is m2 = 0.05 kg

* The initial velocity of m1 is u1 = 0.5 m/s

* The initial velocity of m2 is u2 = 0 m/s

* The final velocity of m1 is v1 = -0.1 m/s

According to the law of conservation of momentum,

[tex]\begin{gathered} m_1u_1+m_2u_2=m_1v_1+m_2v_2 \\ m_1u_1+m_2u_2-m_1v_1=m_2v_2 \\ \frac{(m_1u_1+m_2u_2-m_1v_1)}{m_2}=v_2 \end{gathered}[/tex]

where v2 is the final velocity of the marble B,

Substituting the known values,

[tex]\begin{gathered} \frac{(0.08\times0.5)+(0.05\times0)-(0.08\times(-0.1))}{0.05}=_{}v_{_2} \\ \frac{0.04+0+0.008}{0.05}=v_2_{}_{}_{} \\ \frac{0.04+0.008}{0.05}=v_2 \\ \frac{0.048}{0.05}=v_2 \end{gathered}[/tex]

Thus, the final velocity of the marble B is,

[tex]\begin{gathered} v_2=\frac{0.048}{0.05} \\ v_2=0.96ms^{-1} \end{gathered}[/tex]

Thus, the value of the velocity of the marble B is 0.96 meters per second.

(b). The multiplication of terms 0.08 and -0.1 is,

The term 0.08 can be written as,

[tex]0.08=\frac{8}{100}[/tex]

The term -0.1 can be written as,

[tex]-0.1=\frac{-1}{10}[/tex]

Thus, the multiplication of 0.08 with -0.1 is,

[tex]\begin{gathered} 0.08\times(-0.1)=\frac{8}{100}\times(-\frac{1}{10}) \\ =-(\frac{8}{100}\times\frac{1}{10}) \\ =-\frac{8}{1000} \\ =-0.008 \end{gathered}[/tex]

Thus, the multiplication of 0.08 with -0.1 is -0.008.

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