Connect with experts and get insightful answers to your questions on IDNLearn.com. Our platform offers reliable and detailed answers, ensuring you have the information you need.
Sagot :
Explanation:
Given the reaction:
__ H₂SO₄ (aq) + __ KI (s) ----> __ K₂SO4 (aq) + __ I₂ (g) + __ SO₂ (g) + __ H₂O (l)
First we have to balance it.
__H₂SO₄ (aq) + __ KI (s) ----> __ K₂SO₄ (aq) + __ I₂ (g) + __ SO₂ (g) + __ H₂O (l)
H: 2 H: 2
I: 1 I: 2
K: 1 K: 2
S: 1 S: 2
O: 4 O: 7
We have two atoms of H on both sides, but 1 atom of I and K on the left and 2 atoms of K and I on the right. If we change the coefficient for KI on the left we will balance both elements.
__H₂SO₄ (aq) + 2 KI (s) ----> __ K₂SO₄ (aq) + __ I₂ (g) + __ SO₂ (g) + __ H₂O (l)
H: 2 H: 2
I: 2 I: 2
K: 2 K: 2
S: 1 S: 2
O: 4 O: 7
Now we have two atoms of S on the right and just 1 atom of S on the left. We can change the coefficient for H₂SO₄ and write a 2 there.
2 H₂SO₄ (aq) + 2 KI (s) ----> __ K₂SO₄ (aq) + __ I₂ (g) + __ SO₂ (g) + __ H₂O (l)
H: 4 H: 2
I: 2 I: 2
K: 2 K: 2
S: 2 S: 2
O: 8 O: 7
We balanced the S but unbalanced the H. We have to change the coefficient for H₂O on the right and write a 2 there.
2 H₂SO₄ (aq) + 2 KI (s) ----> __ K₂SO₄ (aq) + __ I₂ (g) + __ SO₂ (g) + 2 H₂O (l)
H: 4 H: 4
I: 2 I: 2
K: 2 K: 2
S: 2 S: 2
O: 8 O: 8
The equation is balanced now. The balanced equation is:
2 H₂SO₄ (aq) + 2 KI (s) ----> K₂SO₄ (aq) + I₂ (g) + SO₂ (g) + 2 H₂O (l)
To find both half reactions we can split these compounds into its ions.
4 H⁺ + 2 SO₄²⁻ + 2 K⁺ + 2 I⁻ ---> 2 K⁺ + SO₄²⁻ + I₂ + SO₂ + 2 H₂O
Let's see which are the species that are changing their oxidations states.
Iodide goes from -1 in I⁻ to 0 in I₂. Its oxidation state is increasing, so it is being oxidized.
Sulfur goes from +6 in SO₄²⁻ to +4 in SO₂. Its oxidation state is decreasing so it is being reduced.
2 I⁻ ---> I₂ oxidation half-reaction
SO₄²⁻ ---> SO₂ reduction half-reaction
Finally we have to balance these equation. To balance the iodine equation we only have to add electrons. To balance the sulfur half-reaction (since it is taking place in an acidic medium) we have to add molecules of water to balance the oxygen atoms, H+ to balance the hydrogen atoms and finally electrons to balance the charges.
2 I⁻ ---> I₂ + 2 e⁻ oxidation half-reaction
SO₄²⁻ ---> SO₂
SO₄²⁻ ---> SO₂ + 2 H₂O
SO₄²⁻ + 4 H⁺ ---> SO₂ + 2 H₂O
SO₄²⁻ + 4 H⁺ + 2 e⁻ ---> SO₂ + 2 H₂O reduction half-reaction
Answer:
2 H₂SO₄ (aq) + 2 KI (s) ----> K₂SO₄ (aq) + I₂ (g) + SO₂ (g) + 2 H₂O (l)
2 I⁻ ---> I₂ + 2 e⁻ oxidation half-reaction
SO₄²⁻ + 4 H⁺ + 2 e⁻ ---> SO₂ + 2 H₂O reduction half-reaction
We are happy to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. For dependable and accurate answers, visit IDNLearn.com. Thanks for visiting, and see you next time for more helpful information.
