IDNLearn.com makes it easy to find precise answers to your specific questions. Ask your questions and receive reliable, detailed answers from our dedicated community of experts.
Sagot :
This is a binomial probability distribution question.
The binomial probability formula is >>>
[tex]P(x)=\frac{n!}{(n-x)!x!}p^xq^{n-x}_{}[/tex]Where
n is the number of trials (number being sampled)
x is the number of success desired
p is the probability of getting a success
q = 1 - p is the probability of failure
From the given problem,
n = 6
x = 3
p = 58% = 0.58
q = 1 - p = 1 - 0.58 = 0.42
Substituting into the formula, we find the probability that exactly 3 of the people use smartphone in meetings or classes:
[tex]\begin{gathered} P(x)=\frac{n!}{(n-x)!x!}p^xq^{n-x}_{} \\ P(x=3)=\frac{6!}{(6-3)!3!}(0.58)^3(0.42)^{6-3}_{} \\ =\frac{6!}{3!3!}(0.58)^3(0.42)^3 \\ =0.2891 \end{gathered}[/tex]
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! Discover the answers you need at IDNLearn.com. Thank you for visiting, and we hope to see you again for more solutions.
