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Sagot :
Answer:
2/3
Explanation:
When a 6-sided standard die is thrown, the sample space is given below:
[tex]\begin{gathered} S=\{1,2,3,4,5,6\} \\ n(S)=6 \end{gathered}[/tex]The events of numbers greater than 2, (say event A) has the outcomes:
[tex]\begin{gathered} A=\{3,4,5,6\} \\ n(A)=4 \end{gathered}[/tex]Therefore, P(number greater than 2) i.e. P(A):
[tex]\begin{gathered} P(A)=\frac{n(A)}{n(S)} \\ =\frac{4}{6} \\ P(A)=\frac{2}{3} \end{gathered}[/tex]The probability of a number greater than 2 is 2/3.
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