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For the following question, find the theoretical probaility of each event when rolling a standard 6 sided die.P(number greater than 2)

Sagot :

Answer:

2/3

Explanation:

When a 6-sided standard die is thrown, the sample space is given below:

[tex]\begin{gathered} S=\{1,2,3,4,5,6\} \\ n(S)=6 \end{gathered}[/tex]

The events of numbers greater than 2, (say event A) has the outcomes:

[tex]\begin{gathered} A=\{3,4,5,6\} \\ n(A)=4 \end{gathered}[/tex]

Therefore, P(number greater than 2)​ i.e. P(A):

[tex]\begin{gathered} P(A)=\frac{n(A)}{n(S)} \\ =\frac{4}{6} \\ P(A)=\frac{2}{3} \end{gathered}[/tex]

The probability of a number greater than 2 is 2/3.

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