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The Parson family is going to a Broadway show. The tickets cost $85 each, there is a charge of $2.50 perticket to pick them up at the box office, a service fee of $10 per order, and they have hired a limousinecompany at a cost of $250 to drive them to and from New York City. If their total cost for tickets andtransportation comes to $785. how many members of the family are attending the show?

Sagot :

Given:

Cost of each ticket = $85 plus a charge of $2.50 per ticket to pick them up.

i e cost of each ticket = 85 + 2.50 = $87.50

A service fee of $10 per order. Here, the family made just one order .

Thus total cost of ticket = $87.50T + $10

Where T represents number of tickets bought.

Cost of limousine ride = $250

The total cost for tickets and transportation comes = $785

To find the number of family members attending the show, we have the equation:

785 = 87.50T + 10 + 250

Let's solve for T:

785 = 87.50T + 260

Subtract 260 from both sides:

785 - 260 = 87.50T + 260 - 260

525 = 87.50T

Divide both sides by 87.50:

[tex]\begin{gathered} \frac{525}{87.50}=\frac{87.50T}{87.50} \\ \\ 6\text{ = T} \end{gathered}[/tex]

T = 6

Since the number of tickets bought is 6, this means that 6 members of the family are attending the show

ANSWER:

6

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