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The nucleus of an atom of 112/49 ln contains:a) 49 protons, 63 neutrons, 49 electronsli) 49 protons, 49 neutrons.c) 49 protons, 49 alpha particlesd) 49 protons, 63 neutronse) 49 protons, 1i2 neutrons

Sagot :

According to the explanation given in the previous session, in this case we have an element with the following configuration: 112/49 X (I will call it X)

A = n + p, atomic mass is the sum of protons and neutrons

Z = p = e, atomic number is equal to number of protons and electrons (in a NEUTRAL atom)

Z = 49, therefore we have 49 protons and 49 electrons

A = 112

112 = 49 + n

n = 112 - 49

n = 63 neutrons

Therefore the best option is letter A, 49 protons, 63 neutrons and 49 electrons

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