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Sagot :
A normal deck of cards has 52 cards, so we know that the total of possibilities is 52.
Now we have to know that the same 52 cards have 4 suits: hearts, clubs, spades, and diamonds. Each suite has 13 cards.
Already, for each sub, we have the same numbers ace, 2, 3, 4,5, 6 ...
That means that we have a probability to draw a diamond of 13/52
And we have a probability to draw a 6 out of 4/52
But remember that exist 1 card which is a diamond 6 so,
Now sum the probabilities:
[tex]P=\frac{13}{52}+\frac{4}{52}-\frac{1}{52}[/tex]I subtract 1/52 because the diamond six has already been counted so the answer is
[tex]P=\text{ }\frac{16}{52}[/tex]ANS: d. none of the above.
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