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Sagot :
Solution:
Given:
[tex]\begin{gathered} A\text{ six-sided die} \\ \\ Possible\text{ outcomes}=1,2,3,4,5,6 \\ Number\text{ of possible outcomes}=6 \end{gathered}[/tex]Even number:
[tex]\begin{gathered} Even\text{ outcomes}=2,4,6 \\ Number\text{ of even outcomes}=3 \\ Probability\text{ of }even,P(even)=\frac{3}{6} \\ P(even)=\frac{1}{2} \end{gathered}[/tex]Odd number:
[tex]\begin{gathered} Odd\text{ numbers}=1,3,5 \\ Number\text{ of odd numbers}=3 \\ Probability\text{ of odd},P(odd)=\frac{3}{6} \\ P(odd)=\frac{1}{2} \end{gathered}[/tex]The expected value is gotten by;
[tex]\begin{gathered} E(x)=\Sigma(x\cdot P(x)) \\ \\ Hence, \\ E(x)=2(\frac{1}{2})+1(\frac{1}{2}) \\ E(x)=1+0.5 \\ E(x)=\text{ \$}1.50 \end{gathered}[/tex]Therefore, the expected value is $1.50
OPTION A is the correct answer.
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