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Sagot :
3415.2 grams
Explanation
to solve this we can use a rule of three
Step 1
Let
water= 100-84%= 16%
so,
[tex]\text{ 16 \%=650 mL}[/tex]for the water , 1 mL = 1 gram , so
[tex]\text{ 16\% =650 grams}[/tex]now, let represents the mass of the aluminiu, so
[tex]\text{ 84 \%= x}[/tex]a) the ratio is the same, so we have a proportion
[tex]\frac{16}{650}=\frac{84}{x}[/tex]Step 2
finally, solve for x
[tex]\begin{gathered} \frac{16}{650}=\frac{84}{x} \\ \text{cross multiply } \\ 16\cdot x=84\cdot650 \\ 16x=54600 \\ \text{divide both sides by 16} \\ \frac{16x}{16}=\frac{54600}{16} \\ x=3412.5 \end{gathered}[/tex]so, the mass of the aluminum is
3415.2 grams
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