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Sagot :
We have the following:
Being a multiplicity of two, then we only have to multiply two factors
We must create a polynomial that, like 0, its solution is 2 and that is -1, in the following way
[tex]\begin{gathered} x=2\Rightarrow x-2=0 \\ x=-1\Rightarrow x+1=0 \\ \text{ we multiply the factors} \\ (x-2)\cdot(x+1)=0 \\ x^2+x-2x-2=0 \\ x^2-x-2=0 \end{gathered}[/tex]Therefore, the answer is the option d.
[tex]f(x)=x^2-x-2[/tex]
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