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The equation of the line is
[tex]3x-8y=30[/tex]To find the point on the x-axis substitute y by 0
[tex]\begin{gathered} 3x-8(0)=30 \\ 3x-0=30 \\ 3x=30 \end{gathered}[/tex]Divide both sides by 3
[tex]\begin{gathered} \frac{3x}{3}=\frac{30}{3} \\ x=10 \end{gathered}[/tex]The point on the x-axis is (10, 0)
To find the point on the y-axis substitute x by 0
[tex]\begin{gathered} 3(0)-8y=30 \\ 0-8y=30 \\ -8y=30 \end{gathered}[/tex]Divide both sides by -8
[tex]\begin{gathered} \frac{-8y}{-8}=\frac{30}{-8} \\ y=-3.75 \end{gathered}[/tex]The point on the y-axis is (0, -3.75)
Let us draw them
The red line represents the equation 3x - 8y = 30
The point on the x-axis is (10, 0)
The point on the y-axis is (0, -3.75)
