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write an equation of the line that passes through the given point and has the given slope (2/3,1), m=-3

Sagot :

The equation of a line has the next form:

y =mx+b

Where m is the slope and b is the y-intercept.

First, we place the slope:

y= -3x+b

to find b, we know that when x = 2/3 the value of y is 1.

So:

1= -3(2/3)+b

Solving for b:

1= -2+b

1+2=b

3=b

So the values are:

m=-3

b=3

The equation of the line is:

y=-3x+3

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