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The rquation using slope intwrcept for the form possible through points (4,6) and (-2,3).

Sagot :

SOLUTION

From the points

[tex]\begin{gathered} (4,\text{ 6) and (-2, 3)} \\ x1=4,x2=-2 \\ y1=6,y2=3 \\ \end{gathered}[/tex]

Using the formula

[tex]\begin{gathered} \frac{y-y1}{x-x1}=\frac{y2-y1}{x2-x1} \\ \\ We\text{ have } \\ \frac{y-6}{x-4}=\frac{3-6}{-2-4} \\ \\ \frac{y-6}{x-4}=\frac{-3}{-6} \\ \\ \frac{y-6}{x-4}=\frac{1}{2} \\ \\ 2(y-6)=x-4 \\ 2y-12=x-4 \\ 2y=x-4+12 \\ 2y=x+8 \\ y=\frac{x}{2}+4 \\ y=\frac{1}{2}x+4 \end{gathered}[/tex]

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