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10. You have 700 grams of Ni3(PO3)2. How many particles are present?

Sagot :

1) List the quantities.

Sample: 700 g Ni3(PO3)2

2) Convert gramas of Ni3(PO3)2 to moles of Ni3(PO3)2.

The molar mass of Ni3(PO3)2 is 334.0241 g/mol.

[tex]mol\text{ }Ni_3(PO_3)_2=700\text{ }g\text{ }Ni_3(PO_3)_2*\frac{1\text{ }mol\text{ }Ni_3(PO_3)_2}{334.0241\text{ }g\text{ }Ni_3(PO_3)_2}=2.10\text{ }mol\text{ }Ni_3(PO_3)_2[/tex]

3) Convert moles to particles.

1 mol = 6.022*10^23 particles.

[tex]parciles\text{ }Ni_3(PO_3)_2=2.10\text{ }mol\text{ }Ni_3(PO_3)_2*\frac{6.022*10^{23}\text{ }particles\text{ }Ni_3(PO_3)_2}{1\text{ }mol\text{ }Ni_3(PO_3)_2}=1.26*10^{24}\text{ }particles[/tex]

700 g Ni3(PO3)2 is equal to 1.26*10^24 particles.