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The length of three sides of a triangle are 3x + 1/2,2x+1/4, and x+1/2
[tex]\begin{gathered} \text{ To solve for the perimeter of a triangle,} \\ \text{ all you need to do is add all the values of the sides} \\ s_1=3x+\frac{1}{2} \\ s_2=2x+\frac{1}{4} \\ s_3=x+\frac{1}{2} \\ P=s_1+s_2+s_3 \\ P=(3x+\frac{1}{2})+(2x+\frac{1}{4})+(x+\frac{1}{2}) \\ P=6x+\frac{5}{4} \end{gathered}[/tex]
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