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Sagot :
[tex]y-6=\frac{5}{4}(x-5),\:y-1=\frac{5}{4}(x-1)[/tex]
1) We need to pick those points (5,6) and (1,1) and find the slope of the line that passes through them.
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{1-6}{1-5}=\frac{-5}{-4}=\frac{5}{4}[/tex]2) Now, we can plug the slope into the Point-Slope form and pick one of those points:
[tex]\begin{gathered} (y_-y_1)=m(x-x_1) \\ \\ (y-6)=\frac{5}{4}(x-5) \\ \\ y-6=\frac{5}{4}(x-5) \\ \\ ----- \\ y-1=\frac{5}{4}(x-1) \\ \\ y-1=\frac{5}{4}(x-1) \\ \\ y-1=\frac{5}{4}(x-1) \end{gathered}[/tex]Once we find the slope, any of those points are suitable. The first option considers point (5,6) and the other one, point (1,1).
3) Thus, this is answer
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