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In A DEF, what is the value of tan D? F 15 D 9 E

Sagot :

solution

For this case we can see that we have a right tirangle and we can find the value of tan D like this:

[tex]EF=\sqrt[]{15^2-9^2}=12[/tex]

Then we have this:

[tex]\tan D=\frac{12}{9}=\frac{4}{3}[/tex]

Then the final answer would be:

4/3

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