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Find 13th term of the arithmetic sequence whose common difference is d=6 and whose first term is a1 =1

Sagot :

Remember that the general formula of an arithmetic sequence is:

[tex]a_n=a_1+d(n-1)[/tex]

Where:

• An is the n-term

,

• d is the common difference

,

• n is the number of the step

Using the given data,

[tex]\begin{gathered} a_{13}=1+6(13-1)\rightarrow a_{13}=1+6(12) \\ \rightarrow a_{13}=73 \end{gathered}[/tex]

Therefore, the 13th term of the arithmetic sequence is 73

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