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The diameter of a cylinder is 4 m. If the height is triple the radius, which is the closest to the volume of the cylinder?

The Diameter Of A Cylinder Is 4 M If The Height Is Triple The Radius Which Is The Closest To The Volume Of The Cylinder class=

Sagot :

Given:

There are given that the diameter of a cylinder is 4m.

Explanation:

The diameter of the cylinder is given 4 m.

Then,

We need to find the value for the radius.

So,

From the formula of the radius:

[tex]r=\frac{d}{2}[/tex]

Then,

Put the value of d into the above formula:

Then,

[tex]\begin{gathered} r=\frac{d}{2} \\ r=\frac{4}{2} \\ r=2m \end{gathered}[/tex]

Now,

According to the question:

The value of height is triple the radius.

So,

The length is:

[tex]l=8[/tex]

Now,

From the formula of volume of the cylinder:

[tex]\begin{gathered} V=\pi r^2h \\ V=3.14\times2^2\times8 \\ V=3.14\times4\times8 \end{gathered}[/tex]

Then,

[tex]\begin{gathered} V=3.14\times32 \\ V=100.48 \end{gathered}[/tex]

Final answer:

Hence, the correct option is D.

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