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Sagot :
hello, this question is about probability.
First of all, we must to sum all the cans of soup that Garry has in his kitchen cabinet.
[tex]\text{3 tomato + 4 chicken + 6 cheese + 7 beef = }20\text{ cans of soup}[/tex]Now, we know that he will choose a random can of soup.
The probability that he will choose a can of chicken soup:
If he has 4 cans of chicken soup, he can take any of them out of a total of 20, right? So we can write this as:
[tex]\frac{4\text{ chicken soup}}{20\text{ total of cans}}=\text{ }\frac{4}{20}=\frac{2}{10}=\frac{1}{5}=0.2\text{ = 20\% probability.}[/tex]For the beef soup, we will do the same process:
[tex]\frac{7\text{ beef soup}}{20\text{ total of cans}}=\text{ }\frac{7}{20}\text{ }=\text{ 35\% of probability}[/tex]But we have a problem, the question asks how likely he is to choose these cans in a row, we can see this by the connective "e".
It's simple, we just need to multiplicate the probabilities of the first case happen by the probability of the second case:
[tex]\frac{4}{20}\times\frac{7}{20}\text{ = }\frac{28}{400}=\frac{14}{200}=\text{ }\frac{7}{100}=\text{ 7\%}[/tex]
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