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A line passes through the point (-9, 5) and has a slope of 4/3. Write an equation in point-slope form for this line.

Sagot :

Solution:

The equation of a line in point-slope form is given by;

[tex]\begin{gathered} y-y_1=m(x-x_1) \\ \\ \text{where m is the slope} \\ \text{and } \\ (x_1,y_1)\text{ is the point} \\ m=\frac{4}{3} \\ x_1=-9 \\ y_1=5 \end{gathered}[/tex]

Substituting these values into the formula;

[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-5=\frac{4}{3}(x-(-9)) \\ y-5=\frac{4}{3}(x+9) \end{gathered}[/tex]

Therefore, the equation of the line in point-slope form is;

[tex]y-5=\frac{4}{3}(x+9)[/tex]

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