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Zeros of graph:
[tex]\begin{gathered} x_1=-6 \\ x_2=2 \end{gathered}[/tex]Vertex: ( -2 , -16 )
Labled point: ( 3, 9 )
To get the quadratic expression:
[tex]y=a(x-h)^2+k[/tex]Where:
• h = -2
,• k = -16
,• x = 3 and y = 6
Then...
[tex]\begin{gathered} 9=a\times(3-(-2))^2+(-16) \\ 9=a\times(5)^2-16 \\ 9=a\times25-16 \\ a=\frac{25}{25}=1 \end{gathered}[/tex]Standard form:
[tex]y=(x+2)^2-16[/tex]General form (solving the quadratic expression):
[tex]y=x^2+4x-12[/tex]Answer: C.