IDNLearn.com is your go-to resource for finding precise and accurate answers. Ask your questions and receive detailed and reliable answers from our experienced and knowledgeable community members.
Sagot :
From the given problem :
[tex]\frac{x^2y^4}{x^2+11x+28}\times\frac{x^2+2x-8}{x^6y^3}[/tex]x^2 + 11x + 28 can be factored as, you need to think of two numbers that has a product of 28 and a sum of 11. In this case it's 7 and 4 :
(x + 7)(x + 4)
and x^2 + 2x - 8 can be factored as, you need to think of two numbers that has a product of -8 and a sum of 2. In this case it's 4 and -2 :
(x + 4)(x - 2)
So the expression will be :
[tex]\frac{x^2y^4}{(x+7)(x+4)}\times\frac{(x+4)(x-2)}{x^6y^3}[/tex]The term (x+4) will be cancelled out
[tex]\frac{x^2y^4(x-2)}{x^6y^3(x+7)}[/tex]Simplify further and the answer is :
[tex]\frac{y(x-2)}{x^4(x+7)}[/tex]
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Find clear answers at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.