IDNLearn.com is designed to help you find reliable answers to any question you have. Discover prompt and accurate answers from our experts, ensuring you get the information you need quickly.
From the given problem :
[tex]\frac{x^2y^4}{x^2+11x+28}\times\frac{x^2+2x-8}{x^6y^3}[/tex]x^2 + 11x + 28 can be factored as, you need to think of two numbers that has a product of 28 and a sum of 11. In this case it's 7 and 4 :
(x + 7)(x + 4)
and x^2 + 2x - 8 can be factored as, you need to think of two numbers that has a product of -8 and a sum of 2. In this case it's 4 and -2 :
(x + 4)(x - 2)
So the expression will be :
[tex]\frac{x^2y^4}{(x+7)(x+4)}\times\frac{(x+4)(x-2)}{x^6y^3}[/tex]The term (x+4) will be cancelled out
[tex]\frac{x^2y^4(x-2)}{x^6y^3(x+7)}[/tex]Simplify further and the answer is :
[tex]\frac{y(x-2)}{x^4(x+7)}[/tex]