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Graph the equation after rewriting it in slope-intercept form. 2x-3y= -6

Sagot :

Consider that in slope-intercept form the equation of a line is given by:

y = mx + b

where m is the slope and b the y-intercept.

Then, solve for y the given equation, as follow:

2x - 3y = -6 subtract 2x both sides

-3y = -2x - 6 divide by -3 both sides

y = 2/3 x + 2

The previous result is the equation is slope-intercept form.

The graph the previous equation, use the a pair of values for x and placed them in the coordinate system, after this, draw a straigh line which crosses the two points, as follow:

where we have use the values of x = -3 and x = 0 and the results for y are:

y = 2/3 (-3) + 2 = - 2 + 2 = 0

y = 2/3(0) + 2 = 2

Which correspond to the shown points (-3,0) and (0,2)

View image AyonW375194
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