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Sagot :
The rule of the volume of the cone is
[tex]V=\frac{1}{3}\times\pi\times r^2\times h[/tex]r is the radius
h is the height
Since the height of the given cone is 11 mm, then
h = 11
Since the radius of it is 4 mm, then
r = 4
Use pi = 3.14
Then substitute these values in the rule above
[tex]\begin{gathered} V=\frac{1}{3}\times3.14\times4^2\times11 \\ V=\frac{1}{3}\times3.14\times16\times11 \\ V=184.21333333mm^3 \end{gathered}[/tex]Round it to the hundredth (2 d.p)
[tex]V=184.21mm^3[/tex]The volume of the cone is 184.21 cubic mm
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